Python 2.7 how parse a date with format 2014-05-01 18:10:38-04:00 [duplicate]

Question

I'm trying to parse this datetime string, without success yet, how can I get it?

d = '2014-05-01 18:10:38-04:00'
datetime.datetime.strptime(d,'%Y-%m-%d %H:%M:%S-%Z')

ValueError: time data '2014-05-01 18:10:38-04:00' does not match format '%Y-%m-%d %H:%M:%S%Z'

Answer 1

You can also use python-dateutil module:

>>> from dateutil import parser
>>> d = '2014-05-01 18:10:38-04:00'
>>> parser.parse(d)
datetime.datetime(2014, 5, 1, 18, 10, 38, tzinfo=tzoffset(None, -14400))

Also see:

• How to parse dates with -0400 timezone string in Python?
• How to convert a timezone aware string to datetime in python without dateutil?

Answer 2

Did you try iso8601 lib? first install it: https://pypi.python.org/pypi/iso8601/

Then:

    import iso8601
    mydate = '2014-05-01 18:10:38-04:00'
    iso8601.parse_date(mydate)

Out[3]: datetime.datetime(2014, 5, 1, 18, 10, 38, tzinfo=<FixedOffset '-04:00'>)