Pyspark AWS credentials

Question

I'm trying to run a PySpark script that works fine when I run it on my local machine. The issue is that I want to fetch the input files from S3.

No matter what I try though I can't seem to be able find where I set the ID and secret. I found some answers regarding specific files ex: Locally reading S3 files through Spark (or better: pyspark) but I want to set the credentials for the whole SparkContext as I reuse the sql context all over my code.

so the question is: How do I set the AWS Access key and secret to spark?

P.S I tried the $SPARK_HOME/conf/hdfs-site.xml and Environment variable options. both didn't work...

Thank you

Answer 1

I'm not sure if this was true at the time, but as of PySpark 2.4.5 you don't need to access the private _jsc object to set Hadoop properties. You can set Hadoop properties using SparkConf.set(). For example:

import pyspark
conf = (
    pyspark.SparkConf()
        .setAppName('app_name')
        .setMaster(SPARK_MASTER)
        .set('spark.hadoop.fs.s3a.access.key', AWS_ACCESS_KEY)
        .set('spark.hadoop.fs.s3a.secret.key', AWS_SECRET_KEY)
)

sc = pyspark.SparkContext(conf=conf)

See https://spark.apache.org/docs/latest/configuration.html#custom-hadoophive-configuration

Answer 2

For pyspark we can set the credentials as given below

  sc._jsc.hadoopConfiguration().set("fs.s3n.awsAccessKeyId", AWS_ACCESS_KEY)
  sc._jsc.hadoopConfiguration().set("fs.s3n.awsSecretAccessKey", AWS_SECRET_KEY)

Answer 3

Setting spark.hadoop.fs.s3a.access.key and spark.hadoop.fs.s3a.secret.key in spark-defaults.conf before establishing a spark session is a nice way to do it.

But, also had success with Spark 2.3.2 and a pyspark shell setting these dynamically from within a spark session doing the following:

spark.sparkContext._jsc.hadoopConfiguration().set("fs.s3a.access.key", AWS_ACCESS_KEY_ID)
spark.sparkContext._jsc.hadoopConfiguration().set("fs.s3a.secret.key", AWS_SECRET_ACCESS_KEY)

And then, able to read/write from S3 using s3a:

documents = spark.sparkContext.textFile('s3a://bucket_name/key')