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PyQt4 File select widget

I want to make a QT4 (using QT designer) dialog, that contains a part where a file has to be selected.

Now, I know QFileDialog exists, and I can program something that does what I want. But can I also just do it in QT designer?

Is there some way to get a "file select" widget in QT designer? Or, I remember these buttons, having the selected file as a title and a little arrow allowing the user to select another file by the QFileDialog?

So is there a ready made solution, or do I have to program it myself?

like image 725
Nathan Avatar asked Jul 07 '10 15:07

Nathan


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3 Answers

There is no file dialog available from the Qt designer as far as I know. But you can easily do it with a few lines of code.

Assuming you have a simple button called pushButton and the path should be stored in lineEdit.

def selectFile():     lineEdit.setText(QFileDialog.getOpenFileName())  pushButton.clicked.connect(selectFile) 

[edit]Just wondering though, are you using KDE by any chance? If so, than you can use the KUrlRequester for this. It can easily be configured to support anything from files to urls to directories.

like image 192
Wolph Avatar answered Sep 26 '22 03:09

Wolph


QFileDialog exists in QtGui. At least in my version 4.4 and probably much earlier too. I think the reason it is not in Designer is because it opens its own window instead of being a widget to place on another window.

The documentation from QTDesigner could be better and at least hint of its existence.

Instantiate it and run the show command. It comes right up and defaults to /.

import QtGui
self.fileDialog = QtGui.QFileDialog(self)
self.fileDialog.show()
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Vicky T Avatar answered Sep 26 '22 03:09

Vicky T


You can use method getOpenFileName() in QFileDialog Class.

QFileDialog.getOpenFileName() will return the file path and the selected file type

I got this : ('C:/Users/Sathsara/Desktop/UI/Test/test.py', 'All Files (*)')

To get only the file path use QFileDialog.getOpenFileName()[0]


Sample code:

def selectFile():
   print(QFileDialog.getOpenFileName()[0])


dlg.locationBtn.clicked.connect(selectFile)
like image 39
Sathsara AM Avatar answered Sep 25 '22 03:09

Sathsara AM