I am writing a pyomo integer programme with a constraint of the form:
def example_rule(model, j, t):
value = sum(model.x[j,i]*(util[i][t]) for i in model.F)
return 0 <= value <= 1
model.onelateral = Constraint(model.L, model.T, rule=example_rule)
util[i][t]
is a dict containing values that are always 0 or 1.
model.x[j,i]
is the binary decision variable.
Sometimes when I run my model, it works fine. However, sometimes when I change the dimensions/values within util[i][t]
it throws this error:
ERROR: Constructing component 'example' from data=None failed:
ValueError: Invalid constraint expression. The constraint expression resolved to a trivial Boolean (True) instead of a Pyomo object. Please modify your rule to return Constraint.Feasible instead of True.
Error thrown for Constraint 'example[L01]'
I cannot find any consistency in why it decides it doesn't like the input values for util[i][t]
. There are never any null values in there.
If I run the model without this constraint in, it works fine all the time.
I have also tried writing the constraint in the form:
def example_rule(model,j):
a = 0
for t in model.T:
n = 0
for i in model.F:
if model.x[j,i].value == 1:
a = model.x[j,i] * util[i][t]
if a == 1:
n = n + a
return 0 <= n <= 1
model.example = Constraint(model.L, rule=example_rule)
But I get the same error message.
I have looked here: https://groups.google.com/forum/#!msg/pyomo-forum/hZXDf7xGnTI/_aiAUN5IwgQJ But this did not help me.
I have tried this using both cbc and glpk solvers. I am using Pyomo V5.2, Python V3.6.1.
Thank you for your help in advance.
Do you have cases where util[i][t] is zero over all i's for a particular t? Terms that are multiplied by zero are automatically removed from the expression so I'm guessing your error is caused by a case where 'value' ends up as zero in which case 0 <= value <= 1 would return a trivial boolean value.
The easiest way to fix this is to formally declare util
as a Param component and add mutable=True
to the declaration. This signals to Pyomo that you might change the value of the util
parameter and therefore avoids the automatic simplification of 0 values.
m.util = Param(m.F, m.T, initialize=util_init, mutable=True)
Another way would be to check the values of util
and skip the constraint if an entire column is zero
def example_rule(model, j, t):
if not any(util[i][t] for i in model.F):
return Constraint.Skip
temp = sum(model.x[j,i]*(util[i][t]) for i in model.F)
return 0 <= temp <= 1
model.onelateral = Constraint(model.L, model.T, rule=example_rule)
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