Here's a simple piece of JavaScript where I want to add the contents of orders.foo
and orders2.foo
to a single-dimensional ordersArr
.
let _ = require('underscore');
let ordersArr = [];
let orders = {
foo: [
{x: 1, b: 2},
{y: 1, c: 3},
{a: 2, d: 4}
]
}
ordersArr = _.map(orders.foo, order => order)
orders2 = {
foo: [
{x: 2, b: 3},
{y: 5, c: 4},
{a: 3, d: 6}
]
}
let tOrders = _.map(orders2.foo, order => order);
ordersArr.push(tOrders)
console.log(ordersArr);
The problem with this code is that push
in this case creates a multi-dimensional array:
Output
[
{ x: 1, b: 2 },
{ y: 1, c: 3 },
{ a: 2, d: 4 },
[ { x: 2, b: 3 }, { y: 5, c: 4 }, { a: 3, d: 6 } ]
]
How do I iterate the contents of orders.foo
and orders2.foo
and have their results as one single dimension array?
You can spread
the content of both arrays into the new array
const arr1 = [1,2,3];
const arr2 = [4,5,6];
const arr3 = [...arr1, ...arr2];
console.log(arr3);
// prints [1,2,3,4,5,6]
Spreading arr2
into arr1
also works.
arr1.push(...arr2);
console.log(arr1);
// prints [1,2,3,4,5,6]
So changing
ordersArr.push(tOrders)
to
ordersArr.push(...tOrders);
should work.
For a full answer:
let ordersArr = [];
let orders = {
foo: [
{x: 1, b: 2},
{y: 1, c: 3},
{a: 2, d: 4}
]
}
orders2 = {
foo: [
{x: 2, b: 3},
{y: 5, c: 4},
{a: 3, d: 6}
]
}
ordersArr.push(...orders.foo, ...orders2.foo);
Using underscore _.flatten
:
const
orders = { foo: [ {x: 1, b: 2}, {y: 1, c: 3}, {a: 2, d: 4} ] },
orders2 = { foo: [ {x: 2, b: 3}, {y: 5, c: 4}, {a: 3, d: 6} ] };
const ordersArr = _.flatten([orders.foo, orders2.foo]);
console.log(ordersArr);
<script src="https://cdnjs.cloudflare.com/ajax/libs/underscore.js/1.8.2/underscore-min.js"></script>
Using javascript spread operator
:
const
orders = { foo: [ {x: 1, b: 2}, {y: 1, c: 3}, {a: 2, d: 4} ] },
orders2 = { foo: [ {x: 2, b: 3}, {y: 5, c: 4}, {a: 3, d: 6} ] };
const ordersArr = [...orders.foo, ...orders2.foo];
console.log(ordersArr);
Using javascript Array#concat
:
const
orders = { foo: [ {x: 1, b: 2}, {y: 1, c: 3}, {a: 2, d: 4} ] },
orders2 = { foo: [ {x: 2, b: 3}, {y: 5, c: 4}, {a: 3, d: 6} ] };
const ordersArr = orders.foo.concat(orders2.foo);
console.log(ordersArr);
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