I'm trying to write a quite simple program that divides an array in another array of defined size smaller arrays, however the push()
method is not working. Could someone please help me with it?
function chunk(array, size) {
var newArray = [];
var tempArray = [];
for (let i = 0; i < array.length / size; i++) {
for (let j = size * i, k = 0; j < size * i + size; j++, k++)
tempArray[k] = array[j];
newArray.push(tempArray);
}
return newArray;
}
var data = [1, 2, 3, 4, 5, 6, 7, 8];
console.log(chunk(data, 2));
The ideal output should be [[1, 2],[3, 4], [5, 6], [7, 8]]
.
However im getting [[7,8],[7,8],[7,8],[7,8]]
.
push() The push() method adds one or more elements to the end of an array and returns the new length of the array.
Alternatives of push() method in JavaScript Approach 1: Use the length property to insert the element at the end of the array. Example: This example implements the above approach.
The opposite of push() (as the question is titled) is pop() .
Because strings are immutable (cannot be modified) any method which attempts to change the string will fail. That immediately rules out methods like push , pop , shift , and splice .
You're almost there. Just move the tempArray
definition inside your first for
-loop. Otherwise you would be pushing the same array each time.
Working Example:
function chunk(array, size) {
const newArray = [];
for (let i = 0; i < array.length / size; i++) {
const tempArray = [];
for (let j = size * i, k = 0; j < size * i + size; j++, k++)
tempArray[k] = array[j];
newArray.push(tempArray);
}
return newArray;
};
const data = [1, 2, 3, 4, 5, 6, 7, 8];
console.log(chunk(data, 2)); // [[1, 2],[3, 4], [5, 6], [7, 8]]
@Behemoth's answer is the correct one for the question. But if you want, you can take a slightly different approach like this to reach the solution as well.
function chunk(array, size){
const newArray = [];
let i,j;
for (i = 0,j = array.length; i < j; i += size) {
newArray.push(array.slice(i, i + size));
}
return newArray;
};
var data = [1, 2, 3, 4, 5, 6, 7 ,8];
console.log(chunk(data, 2));
Slightly different solution than @Behemoth and @Rukshan
function chunk(array, size) {
var newArray = [];
var tempArray = [];
for (let i = 0; i < array.length / size; i++) {
for (let j = i; j < i + 1; j++) {
for (let k = 0; k < size; k++) {
if (array[size * j + k]) {
tempArray.push(array[size * j + k]);
}
}
newArray.push(tempArray);
tempArray = [];
}
}
return newArray;
};
var data = [1, 2, 3, 4, 5, 6, 7, 8];
console.log(chunk(data, 2));
The solution would be [ [ 1, 2 ], [ 3, 4 ], [ 5, 6 ], [ 7, 8 ], [ 9 ] ] instead of [ [ 1, 2 ], [ 3, 4 ], [ 5, 6 ], [ 7, 8 ]]
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