Generic specialization along with value types are a projected feature of future JVMs; link to the Valhalla project page here.
Now, from what I understand, it would then become possible to declare a:
final List<int> myList = new ArrayList<>(); // for instance
But then List
defines another .remove()
method in addition to the one defined in the Collection
interface, which takes an int
as an argument which is the index in the list to remove; that is why, currently, the content of list
in the example below:
final List<Integer> list = new ArrayList<>();
list.add(1);
list.add(2);
list.add(3);
list.remove(2);
will be [1, 2]
and not [1, 3]
(the most specific overload is chosen).
However, if in the future we are able to declare a List<int>
, we have a problem: what overload of the remove
method will be chosen?
remove() (in Map as well as in Collection ) is not generic because you should be able to pass in any type of object to remove() . The object removed does not have to be the same type as the object that you pass in to remove() ; it only requires that they be equal.
Generics enable the use of stronger type-checking, the elimination of casts, and the ability to develop generic algorithms. Without generics, many of the features that we use in Java today would not be possible.
Whenever you want to restrict the type parameter to subtypes of a particular class you can use the bounded type parameter. If you just specify a type (class) as bounded parameter, only sub types of that particular class are accepted by the current generic class.
This answer is based on this paper by Brian Goetz, dated December 2014. This is the latest I could find on the subject; note however that the paper is an "informal sketch" so there's nothing definitive yet regarding your question.
First, a List<int>
would not be a subtype of List<Integer>
(Subtyping):
Initially, it might also seem sensible that
Box<int>
could be a subtype of rawBox
. But, given our translation strategy, theBox
class cannot be a superclass of whatever class representsBox<int>
, as thenBox<int>
would have a fieldt
of typeObject
, whereast
should be of typeint
. SoBox<int>
cannot be a subtype of rawBox
. (And for the same reason,Box<int>
cannot be a subtype ofBox<Integer>
.)...
Since generics are invariant, it is not surprising that
List<int>
is not a subtype ofList<Integer>
. The slightly surprising thing here is that a specialized type cannot interoperate with its raw counterpart. However, this is not an unreasonable restriction; not only are raw types discouraged (having been introduced solely for the purpose of supporting the gradual migration from non-generic code to generic code), but it is still possible to write fully generic code using generic methods -- see "Generic Methods".
This paper also lists "Migration challenges", and reference-primitive overloadings (the problem is your question) is one of them:
Some overloadings that are valid today would become problematic under specialization. For example, these methods would have a problem if specialized with
T=int
:public void remove(int position); public void remove(T element);
Such overloads would be problematic both on the specialization side (what methods to generate) and on the overload selection side (which method to invoke.)
A proposed solution is refered to as the "peeling" technique:
Consider the overload pair in a List-like class:
interface ListLike<T> { public void remove(int position); public void remove(T element); }
Existing uses of
ListLike
will all involve reference instantiations, since those are the only instantiations currently allowed in a pre-specialization world. Note that while compatibility requires that reference instantiations have both of these methods, it requires nothing of non-reference instantiations (since none currently exist.)The intuition behind peeling is to observe that, while we're used to thinking of the existing
ListLike
as the generic type, that it might really be the union of a type that is generic across all instantiations, and a type that is generic across only reference instantations.If we were writing this class from scratch in a post-specialization world, we might have written it as:
interface ListLike<any T> { void removeByIndex(int position); void removeByValue(T element); }
But, such a change now would not be either source-compatible or binary-compatible. However, peeling allows us to add these methods to the generic layer, and implement them in a reference-specific layer, without requiring them in the specializations, restoring compatibility:
interface ListLike<any T> { // New methods added to the generic layer void removeByValue(T element); void removeByIndex(int pos); layer<ref T> { // Abstract methods that exist only in the ref layer void remove(int pos); void remove(T element); // Default implementations of the new generic methods default void removeByIndex(int pos) { remove(pos); } default void removeByValue(T t) { remove(t); } } }
Now, reference instantiations have
remove(T)
, andremove(int)
(as well as the new methodsremoveByIndex
andremoveByValue
), ensuring compatibility, and specializations have the nonproblematic overloads ofremoveByValue(T)
andremoveByIndex(int)
. Existing implementations ofListLike
would continue to compile since the new methods have a default implementation for reference specializations (which simply bridges to the existing remove methods). For value instantiations,removeByIndex
andremoveByValue
are seen as abstract and must be provided, but remove does not exist at all.This technique also enables the "implementation by parts" technique; it is possible to declare a method abstract in the generic layer and provide concrete implementations in both the value and reference layers. If we allowed layers for
T=int
, it would also enable the "specializing the specializations" technique.
With this technique, backward compatibility would be kept and the new methods removeByValue
and removeByIndex
would be used.
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