Program aborts when using strcpy on a char pointer? (Works fine on char array)

Question

I'm perplexed as to why the following doesn't work:

char * f = "abcdef";
strcpy(f, "abcdef");
printf("%s",f);

char s[] = "ddd";
strcpy(&s[0], "eee");
printf("%s", s);

In both examples strcpy received a char * yet on the first example it dies a horrible death.

Answer 1

"abcdef" and "ddd" are string literals which may reside in a read-only section of your address space. char s[] = "ddd" ensures this literal is copied to stack - so it's modifiable.

Answer 2

char * f = "abcdef"; defines a char pointer to "abcdef" which is located in read-only area so you can't write to this place

char s[] = "ddd"; defines a char array on the stack which is writable.