Produce a string from a tuple

Question

I am looking for a nice, efficient and pythonic way to go from something like this:

('zone1', 'pcomp110007')

to this:

'ZONE 1, PCOMP 110007'

without the use of regex if possible (unless it does make a big difference that is..). So turn every letter into uppercase, put a space between letters and numbers and join with a comma.

What i wrote is the following:

tags = ('zone1', 'pcomp110007')


def sep(astr):
    chars = ''.join([x.upper() for x in astr if x.isalpha()])
    nums = ''.join([x for x in astr if x.isnumeric()])
    return chars + ' ' + nums

print(', '.join(map(sep, tags)))

Which does produce the desired result but looks a bit too much for the task.

The tuple might vary in length but the numbers are always going to be at the end of each string.

Answer 1

Regex does help. This should always work:

import re
tags = ('zone1', 'pcomp110007')

def sep(s):
    word = re.split(r'\d', s)[0]
    return word.upper() + " " + s[len(word):]

print(', '.join(map(sep, tags)))

Answer 2

My thoughts:

Keep sep a normal function like it is in your original code for readability / maintenance, but also leverage re as suggested in Abdou's answer.

import re
tags = ('zone1', 'pcomp110007')

def sep(astr):
    alpha, num = re.match('([^\d]+)([\d]+)', astr).groups()
    return '{} {}'.format(alpha.upper(), num) 

print(', '.join(map(sep, tags)))

Edit: Note that if you prefer, I think it would also be reasonable to just return:

return alpha.upper() + ' ' + num

Or older style string formatting:

return '%s %s' %(alpha.upper(), num)

Whatever you're most comfortable with.

Answer 3

Using re:

import re

tupl = ('zone1', 'pcomp110007')

", ".join(map(lambda x: " ".join(re.findall('([A-Z]+)([0-9])+',x.upper())[0]), tupl))

#'ZONE 1, PCOMP 7'