The following code works as expected with boost 1.57:
#include <iostream>
#include <boost/log/trivial.hpp>
struct Foo
{
int d=1;
};
std::ostream& operator<<(std::ostream& out, const Foo& foo)
{
out << "Foo: " << foo.d;
return out;
}
int main()
{
BOOST_LOG_TRIVIAL(info) << Foo();
return EXIT_SUCCESS;
}
with boost 1.59 the same code fails. The first gcc error message is:
error: no match for ‘operator<<’ (operand types are ‘boost::log::v2s_mt_posix::basic_record_ostream’ and ‘Foo’)
Neither the documentation nor the release notes document what needs to be changed.
Live version
Looks like problem is in enable_if_formatting_ostream
struct. It was added in this commit. And looks like
template< typename StreamT, typename R >
struct enable_if_formatting_ostream {};
template< typename CharT, typename TraitsT, typename AllocatorT, typename R >
struct enable_if_formatting_ostream< basic_formatting_ostream< CharT, TraitsT, AllocatorT >, R > { typedef R type; };
And now operator <<
is
template< typename StreamT, typename T >
inline typename boost::log::aux::enable_if_formatting_ostream< StreamT, StreamT& >::type
operator<< (StreamT& strm, T const& value)
Before it was
template< typename CharT, typename TraitsT, typename AllocatorT, typename T >
inline basic_formatting_ostream< CharT, TraitsT, AllocatorT >&
operator<< (basic_formatting_ostream< CharT, TraitsT, AllocatorT >& strm, T const& value)
and since record_ostream
is derived from formatting_ostream
compiler can find overload, but now not, since SFINAE is used and struct will have type
typedef only when formatting_ostream
is used. And this can be workaround for this case.
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