Priority of the logical statements NOT AND & OR in python

Question

As far as I know, in C & C++, the priority sequence for NOT AND & OR is NOT>AND>OR. But this doesn't seem to work in a similar way in Python. I tried searching for it in the Python documentation and failed (Guess I'm a little impatient.). Can someone clear this up for me?

Answer 1

It's NOT, AND, OR, from highest to lowest according to the documentation on Operator precedence

Here is the complete precedence table, lowest precedence to highest. A row has the same precedence and chains from left to right

 0. :=  1. lambda  2. if – else  3. or  4. and  5. not x  6. in, not in, is, is not, <, <=, >, >=, !=, ==  7. |  8. ^  9. &  10. <<, >>  11. +, -  12. *, @, /, //, %  13. +x, -x, ~x  14. **  14. await x  15. x[index], x[index:index], x(arguments...), x.attribute  16. (expressions...), [expressions...], {key: value...}, {expressions...} 

Answer 2

You can do the following test to figure out the precedence of and and or.

First, try 0 and 0 or 1 in python console

If or binds first, then we would expect 0 as output.

In my console, 1 is the output. It means and either binds first or equal to or (maybe expressions are evaluated from left to right).

Then try 1 or 0 and 0.

If or and and bind equally with the built-in left to right evaluation order, then we should get 0 as output.

In my console, 1 is the output. Then we can conclude that and has higher priority than or.