println() method in Java for Strings equality ... and how it works exactly? [duplicate]

Question

I am trying to understand the working of System.out.println() in Java... in following 2 code snippet , why the answer is different and why it do not print "Hello: " string inside println() method ?

 public static void main(String[] args) {
        String x = "abc";
        String y = "abc";
        System.out.println("Hello:" + x == y);
        System.out.println("x.equals(y): " + x.equals(y));

        if(x == y){
            System.out.println("Hello:" + x==y);
        }

}

Answer is :

false
x.equals(y): true
false

And for second code snippet :

 public static void main(String[] args) {
        String x = "abc";
        String y = "abc";

        System.out.println( x == y);

        System.out.println("x.equals(y): " + x.equals(y));

        if(x == y){
            System.out.println(x==y);
        }

}

The answer is:

true
x.equals(y): true
true

Answer 1

This is due to operator precedence: "Hello:" + x == y is equivalent to ("Hello:" + x) == y.

Because + has a higher precedence than ==.