Printf variable number of decimals in float

Question

I found interesting format for printing nonterminated fixed length strings like this:

char newstr[40] = {0}; sprintf(newstr,"%.*s",  sizeof(mystr), mystr); 

So I think maybe is there a way under printf command for printing a float number...

"%8.2f"

to have ability to choose number of decimals with integer number.

Something like this:

sprintf(mystr, "%d %f", numberofdecimals, floatnumbervalue) 

Answer 1

You can also use ".*" with floating points, see also http://www.cplusplus.com/reference/cstdio/printf/ (refers to C++, but the format specifiers are similar)

.number: For a, A, e, E, f and F specifiers: this is the number of digits to be printed after the decimal point (by default, this is 6).

...

.*: The precision is not specified in the format string, but as an additional integer value argument preceding the argument that has to be formatted.

For example:

float floatnumbervalue = 42.3456; int numberofdecimals = 2; printf("%.*f", numberofdecimals, floatnumbervalue); 

Output:

42.35