printf format specifiers for uint32_t and size_t

Question

Try

#include <inttypes.h>
...

printf("i [ %zu ] k [ %"PRIu32" ]\n", i, k);

The z represents an integer of length same as size_t, and the PRIu32 macro, defined in the C99 header inttypes.h, represents an unsigned 32-bit integer.

Sounds like you're expecting size_t to be the same as unsigned long (possibly 64 bits) when it's actually an unsigned int (32 bits). Try using %zu in both cases.

I'm not entirely certain though.

All that's needed is that the format specifiers and the types agree, and you can always cast to make that true. long is at least 32 bits, so %lu together with (unsigned long)k is always correct:

uint32_t k;
printf("%lu\n", (unsigned long)k);

size_t is trickier, which is why %zu was added in C99. If you can't use that, then treat it just like k (long is the biggest type in C89, size_t is very unlikely to be larger).

size_t sz;
printf("%zu\n", sz);  /* C99 version */
printf("%lu\n", (unsigned long)sz);  /* common C89 version */

If you don't get the format specifiers correct for the type you are passing, then printf will do the equivalent of reading too much or too little memory out of the array. As long as you use explicit casts to match up types, it's portable.

If you don't want to use the PRI* macros, another approach for printing ANY integer type is to cast to intmax_t or uintmax_t and use "%jd" or %ju, respectively. This is especially useful for POSIX (or other OS) types that don't have PRI* macros defined, for instance off_t.

How do I print uint32_t and uint16_t variables' value?

#include <stdio.h>     // need at least one of these two
#include <inttypes.h>
int main (void) {
    uint32_t a=1234;
    uint16_t b=5678;
    printf("%" PRIu32 "\n",a);
    printf("%" PRIu16 "\n",b);
    return 0;
}