My C program is pasted below. In bash, the program print "char is ", Ω is not printed. My locale are all en_US.utf8.
#include <stdio.h>
#include <wchar.h>
#include <stdlib.h>
int main() {
int r;
wchar_t myChar1 = L'Ω';
r = wprintf(L"char is %c\n", myChar1);
}
This was quite interesting. Apparently the compiler translates the omega from UTF-8 to UNICODE but somehow the libc messes it up.
First of all: the %c
-format specifier expects a char
(even in the wprintf-version) so you have to specify %lc
(and therefore %ls
for strings).
Secondly if you run your code like that the locale is set to C
(it isn't automatically taken from the environment). You have to call setlocale
with an empty string to take the locale from the environment, so the libc is happy again.
#include <stdio.h>
#include <wchar.h>
#include <stdlib.h>
#include <locale.h>
int main() {
int r;
wchar_t myChar1 = L'Ω';
setlocale(LC_CTYPE, "");
r = wprintf(L"char is %lc (%x)\n", myChar1, myChar1);
}
Alternatively to the answer suggesting fixing LIBC, you can do this:
#include <stdio.h>
#include <wchar.h>
#include <stdlib.h>
// NOTE: *NOT* thread safe, not re-entrant
const char* unicode_to_utf8(wchar_t c)
{
static unsigned char b_static[5];
unsigned char* b = b_static;
if (c<(1<<7))// 7 bit Unicode encoded as plain ascii
{
*b++ = (unsigned char)(c);
}
else if (c<(1<<11))// 11 bit Unicode encoded in 2 UTF-8 bytes
{
*b++ = (unsigned char)((c>>6)|0xC0);
*b++ = (unsigned char)((c&0x3F)|0x80);
}
else if (c<(1<<16))// 16 bit Unicode encoded in 3 UTF-8 bytes
{
*b++ = (unsigned char)(((c>>12))|0xE0);
*b++ = (unsigned char)(((c>>6)&0x3F)|0x80);
*b++ = (unsigned char)((c&0x3F)|0x80);
}
else if (c<(1<<21))// 21 bit Unicode encoded in 4 UTF-8 bytes
{
*b++ = (unsigned char)(((c>>18))|0xF0);
*b++ = (unsigned char)(((c>>12)&0x3F)|0x80);
*b++ = (unsigned char)(((c>>6)&0x3F)|0x80);
*b++ = (unsigned char)((c&0x3F)|0x80);
}
*b = '\0';
return b_static;
}
int main() {
int r;
wchar_t myChar1 = L'Ω';
r = printf("char is %s\n", unicode_to_utf8(myChar1));
return 0;
}
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