print result of map function call in pdb [duplicate]

Question

In debugging my code, I want to use a list comprehension. However, it seems I cannot evaluate a list comprehension from the debugger when I'm inside a function.

I am using Python 3.4.

Script contents:

$ cat test.py 
#!/usr/bin/python

def foo():
    x = [1, 2, 3, 3, 4]

    print(x)

foo()

Interactive debugging:

$ python3 -mpdb test.py                                                                                                                                           
> /tmp/test.py(3)<module>()
-> def foo():
(Pdb) step
> /tmp/test.py(8)<module>()
-> foo()
(Pdb) 
--Call--
> /tmp/test.py(3)foo()
-> def foo():
(Pdb) 
> /tmp/test.py(4)foo()
-> x = [1, 2, 3, 3, 4]
(Pdb) 
> /tmp/test.py(6)foo()
-> print(x)
(Pdb) p [x for _ in range(1)]
*** NameError: name 'x' is not defined
(Pdb) p x
[1, 2, 3, 3, 4]

Why is x unknown to the list comprehension? How could I evaluate a list comprehension from the debugger, or achieve an equivalent behaviour? Is this a bug, or is it some sort of fundamental limitation to the debugger?

Answer 1

In Python 3, you have to use the interact command in pdb before you can access any non-global variables due to a change in the way comprehensions are implemented.

>>> def foo(): [][0]
... 
>>> foo()
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "<stdin>", line 1, in foo
IndexError: list index out of range
>>> import pdb;pdb.pm()
> <stdin>(1)foo()
(Pdb) x = 4
(Pdb) [x for _ in range(2)]
*** NameError: name 'x' is not defined
(Pdb) interact
*interactive*
>>> [x for _ in range(2)]
[4, 4]
>>>