Print list of lists in separate lines

Question

I have a list of lists:

a = [[1, 3, 4], [2, 5, 7]]

I want the output in the following format:

1 3 4
2 5 7

I have tried it the following way , but the outputs are not in the desired way:

for i in a:
    for j in i:
        print(j, sep=' ')

Outputs:

1
3
4
2
5
7

While changing the print call to use end instead:

for i in a:
    for j in i:
        print(j, end = ' ')

Outputs:

1 3 4 2 5 7

Any ideas?

Answer 1

Iterate through every sub-list in your original list and unpack it in the print call with *:

a = [[1, 3, 4], [2, 5, 7]]
for s in a:
    print(*s)

The separation is by default set to ' ' so there's no need to explicitly provide it. This prints:

1 3 4
2 5 7

In your approach you were iterating for every element in every sub-list and printing that individually. By using print(*s) you unpack the list inside the print call, this essentially translates to:

print(1, 3, 4)  # for s = [1, 3, 4]
print(2, 5, 7)  # for s = [2, 5, 7]

Answer 2

oneliner:

print('\n'.join(' '.join(map(str,sl)) for sl in l))

explanation:
you can convert list into str by using join function:

l = ['1','2','3']
' '.join(l) # will give you a next string: '1 2 3'
'.'.join(l) # and it will give you '1.2.3'

so, if you want linebreaks you should use new line symbol.
But join accepts only list of strings. For converting list of things to list of strings, you can apply str function for each item in list:

l = [1,2,3]
' '.join(map(str, l)) # will return string '1 2 3'

And we apply this construction for each sublist sl in list l