Condider the following snippet:
<template v-if="tryIsMobile" >
<div class='device device-mobile-portrait' :class="deviceClass">
<div class="device-scroller-container">
<div class='device-scroller'>
<img id='tryit-img-mobile' :src="srcUrlMobile" v-on:load="onImgLoad" v-on:error="onImgError"/>
</div>
</div>
</div>
</template>
<template v-else>
<div class='device device-tablet-landscape' :class="deviceClass" >
<div class="device-scroller-container">
<div class='device-scroller'>
<img id='tryit-img-tablet' :src="srcUrlTablet" v-on:load="onImgLoad" v-on:error="onImgError"/>
</div>
</div>
</div>
</template>
This code conditionally renders one of the two images. Some user action results in the actual shown image to be toggled.
What I'm seeing is the following: When toggling from say, tryit-img-mobile
to tryit-img-tablet
, the image loaded as part of tryit-img-mobile
will get displayed with different dimensions instantly. However, during the time the image loads it's new source :src="srcUrlTablet"
, the image with src :src="srcUrlMobile"
still displays.
This is probably due to Vue using the same img-tag for both the templates. How can I prevent Vue from doing this, and instead use seperate img-tags?
In cases such as this, Vue uses a special key
attribute that tells it not to reuse the same element. Give each element this attribute with a unique value, and Vue will no longer reuse the same element:
<div v-if="tryIsMobile"
class="device device-mobile-portrait"
:class="deviceClass"
key="mobile"
>
...
</div>
<div v-else
class="device device-tablet-landscape"
:class="deviceClass"
key="tablet"
>
...
</div>
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With