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Preventing dividing by zero in list comprehensions

I have the following code:

scores = [matrix[i][i] / sum(matrix[i]) for (i, scores) in enumerate(matrix)]

My problem is that sum(matrix[i]) could be 0 in some cases, resulting in a ZeroDivisionError. But because matrix[i][i] is also 0 in that case, I solved this as follows:

scores = [divide(matrix[i][i], sum(matrix[i])) for (i, scores) in enumerate(matrix)]

The function divide(x, y) returns 1 if y == 0 and (x / y) if y > 0. But I wonder if there is an easier way. Maybe I could use some ternary operator, but does that exist in Python?

like image 251
Lewistrick Avatar asked Jun 21 '13 12:06

Lewistrick


2 Answers

Yes, in Python it's called the conditional expression:

[matrix[i][i] / sum(matrix[i]) if sum(matrix[i]) != 0 else 0 
 for (i, scores) in enumerate(matrix)]
like image 182
TerryA Avatar answered Oct 26 '22 03:10

TerryA


[(lambda x, y: 0 if y == 0 else x/y)(row[i], sum(row))
 for i, row in enumerate(matrix)]
like image 29
falsetru Avatar answered Oct 26 '22 02:10

falsetru