Prettiest way to iterate all values of an unsigned integer

Question

I want to iterate all possible values of an integer. This code does not work as the termination condition never becomes false:

for (uint32_t i = 0; i <= 0xFFFFFFFF; i++)
    std::cout << i << std::endl;

I've come up with this:

auto loopBody = [](uint32_t value)
{
    std::cout << value << std::endl;
};

uint32_t last = 0xFFFFFFFF;
for (uint32_t i = 0; i < last; i++)
    loopBody(i);

loopBody(last);

It is fairly ugly, though. Is there a prettier way to do this?

Answer 1

I would use something like this:

uint32_t i = 0;
do
{
    // Your code here.
    i++;
}
while (i != 0);

I personally find it more elegant than a solution involving std::numeric_limits.

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As @NicosC said, keep in mind that you should not do same trick with signed integers, because signed overflow is undefined behavior.