Porting struct.unpack from python 2.7 to 3

Question

The following code works fine in python 2.7:

def GetMaxNoise(data, max_noise):
    for byte in data:
        noise = ComputeNoise(struct.unpack('=B',byte)[0])
        if max_noise < noise:
            max_noise = noise
    return max_noise

where data is a string holding binary data (taken from a network packet).

I'm trying to port it to Python 3 and I get this:

File "Desktop/Test.py", line 2374, in GetMaxNoise

noise = ComputeNoise(struct.unpack('=B',byte)[0])

TypeError: 'int' does not support the buffer interface

How can I convert "data" to the appropriate type needed by unpack()?

Answer 1

Assuming the data variable is a string of bytes that you got from a binary file on a network packet, it it not processed the same in Python2 and Python3.

In Python2, it is a string. When you iterate its values, you get single byte strings, that you convert to int with struct.unpack('=B')[0]

In Python3, it is a bytes object. When you iterate its values, you directly get integers! So you should directly use:

def GetMaxNoise(data, max_noise):
    for byte in data:
        noise = ComputeNoise(byte)  # byte is already the int value of the byte...
        if max_noise < noise:
            max_noise = noise
    return max_noise

Answer 2

From the docs of the struct module https://docs.python.org/3.4/library/struct.html I see that the unpack method expects it's second argument to implement Buffer Protocol, so it generally expects bytes.

Your data object seems to be of the type bytes as it's read from somewhere. When you iterate over it with the for loop, you end up with byte variable being single int values.

I don't know what your code is supposed to do and how, but maybe change the way you iterate over your data object to handle not ints but bytes of length == 1?

for i in range(len(data)):
    byte = data[i:i+1]
    print(byte)