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The polygon points along with the uncut, original image are sent by client to the server.
Is there a way that I can clip (crop) the original image along these points in Python server, and save the cropped image? I am currently using PIL, and would prefer a PIL or PIL extended solution.
Thanks in advance
962
crop() method is used to crop a rectangular portion of any image. Parameters: box – a 4-tuple defining the left, upper, right, and lower pixel coordinate. Return type: Image (Returns a rectangular region as (left, upper, right, lower)-tuple).
Use resize() to resize the whole image instead of cutting out a part of the image, and use putalpha() to create a transparent image by cutting out a shape other than a rectangle (such as a circle). Use slicing to crop the image represented by the NumPy array ndarray . Import Image from PIL and open the target image.
PIL is the Python Imaging Library which provides the python interpreter with image editing capabilities. The Image module provides a class with the same name which is used to represent a PIL image.
I found a solution using numpy and PIL- so thought I will share:
import numpy
from PIL import Image, ImageDraw
# read image as RGB and add alpha (transparency)
im = Image.open("crop.jpg").convert("RGBA")
# convert to numpy (for convenience)
imArray = numpy.asarray(im)
# create mask
polygon = [(444,203),(623,243),(691,177),(581,26),(482,42)]
maskIm = Image.new('L', (imArray.shape[1], imArray.shape[0]), 0)
ImageDraw.Draw(maskIm).polygon(polygon, outline=1, fill=1)
mask = numpy.array(maskIm)
# assemble new image (uint8: 0-255)
newImArray = numpy.empty(imArray.shape,dtype='uint8')
# colors (three first columns, RGB)
newImArray[:,:,:3] = imArray[:,:,:3]
# transparency (4th column)
newImArray[:,:,3] = mask*255
# back to Image from numpy
newIm = Image.fromarray(newImArray, "RGBA")
newIm.save("out.png")
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