PIL Image mode I is grayscale?

Question

I'm trying to specify the colours of my image in Integer format instead of (R,G,B) format. I assumed that I had to create an image in mode "I" since according to the documentation:

The mode of an image defines the type and depth of a pixel in the image. The current release supports the following standard modes:

• 1 (1-bit pixels, black and white, stored with one pixel per byte)
• L (8-bit pixels, black and white)
• P (8-bit pixels, mapped to any other mode using a colour palette)
• RGB (3x8-bit pixels, true colour)
• RGBA (4x8-bit pixels, true colour with transparency mask)
• CMYK (4x8-bit pixels, colour separation)
• YCbCr (3x8-bit pixels, colour video format)
• I (32-bit signed integer pixels)
• F (32-bit floating point pixels)

However this seems to be a grayscale image. Is this expected? Is there a way of specifying a coloured image based on a 32-bit integer? In my MWE I even let PIL decide how to convert "red" to the "I" format.

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MWE

from PIL import Image

ImgRGB=Image.new('RGB', (200,200),"red") # create a new blank image
ImgI=Image.new('I', (200,200),"red") # create a new blank image
ImgRGB.show()
ImgI.show()

Answer 1

Is there a way of specifying a coloured image based on a 32-bit integer?

Yes, use the RGB format for that, but instead use an integer instead of "red" as the color argument:

from PIL import Image

r, g, b = 255, 240, 227
intcolor = (b << 16 ) | (g << 8 ) | r                                       
print intcolor # 14938367
ImgRGB = Image.new("RGB", (200, 200), intcolor)
ImgRGB.show()