In my code I've module M = Implementation1
and then I reference M
, instead of Implementation1
. The problem is, I've to recompile my program to change Implementation1
to Implementation2
. I'd like to control which implementation to use from with a command line parameter. Is that possible?
Is the situation simpler, when all implementations share signature?
Since both implementation are known statically you can use first class modules. There are quite a few different possibilities on how to structure your program, here's one that minimizes toplevel reference cells and toplevel effectful statements:
module type M = sig
val test : unit -> unit
end
module M1 : M = struct
let test () = Printf.printf "Implementation 1\n%!"
end
module M2 : M = struct
let test () = Printf.printf "Implementation 2\n%!"
end
let test m =
let module M = (val m : M) in
(* If other modules of your program depend on the implementation of
M, functorize them over sig M and instantiate them with M here. *)
M.test ()
let main () =
let exec = Filename.basename Sys.executable_name in
let usage = Printf.sprintf
"Usage: %s [OPTION]...\n\
Program synopsis.\n\
Options:" exec
in
let m = ref (module M1 : M) in
let options = [
"-m1", Arg.Unit (fun () -> m := (module M1 : M)),
" Use implementation 1 (default)";
"-m2", Arg.Unit (fun () -> m := (module M2 : M)),
" Use implementation 2"; ]
in
let anon _ = raise (Arg.Bad "no positional argument supported") in
Arg.parse (Arg.align options) anon usage;
test !m
let () = main ()
For most versions of OCaml you can do this with camlp4.
IFDEF USE_IMP1 THEN
module M = Implementation1
ELSE
module M = Implementation2
END
Then passing the pre-processing options like the following will choose the correct one to incorporate in the build.
-pp "camlp4of -UUSE_IMP1" //to undefine USE_IMP1
-pp "camlp4of -DUSE_IMP1" //to define USE_IMP2
For versions of OCaml >= 4.00.0 you can use the First-Class modules and an expression like,
module Choose = (val (if use_impl1 then (module Impl_1) else (module Impl_2)) : IMP)
to use an if statement to choose the module as determined by the use_impl1
value.
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