Picking input record fields with AWK

Question

Let's say we have a shell variable $x containing a space separated list of numbers from 1 to 30:

$ x=$(for i in {1..30}; do echo -n "$i "; done)
$ echo $x
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30

We can print the first three input record fields with AWK like this:

$ echo $x | awk '{print $1 " " $2 " " $3}'
1 2 3

How can we print all the fields starting from the Nth field with AWK? E.g.

4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30

EDIT: I can use cut, sed etc. to do the same but in this case I'd like to know how to do this with AWK.

Answer 1

Converting my comment to answer so that solution is easy to find for future visitors.

You may use this awk:

awk '{for (i=3; i<=NF; ++i) printf "%s", $i (i<NF?OFS:ORS)}' file

or pass start position as argument:

awk -v n=3 '{for (i=n; i<=NF; ++i) printf "%s", $i (i<NF?OFS:ORS)}' file