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PHP/GD, how to copy a circle from one image to another?

Is there a reasonably straightforward way to copy a circular area from one image resource to another? Something like imagecopymerge except with circles or ovals etc?
If possible, I want to avoid having to use pre-created image files (any oval shape should be possible), and if there's transparency colours involved they should naturally leave the rest of the image alone.

Reason I'm asking, I have a few classes that allow to apply image operations inside a "selected area" of an image, which works by first deleting that area from a copy of the image, then overlaying the copy back on the original. But what if you want to select a rectangle, and then inside that deselect a circle, and have the operations only affect the area that's left?

like image 968
MSpreij Avatar asked Jun 29 '09 00:06

MSpreij


1 Answers

You could try this:

  1. Start with original image - $img
  2. Copy that image to a png - $copy
  3. Create a mask png image of the area you want in the circle/ellipse (a 'magicpink' image with a black shape on it, with black set to the colour of alpha transparency) - $mask
  4. Copy $mask over the top of $copy maintaining the Alpha transparency
  5. Change what you need to on $copy
  6. Copy $copy back over $img maintaining the Alpha transparency

    // 1. Start with the original image  
    $img = imagecreatefromjpeg("./original.jpg");  
    $img_magicpink = imagecolorallocatealpha($img, 255, 0, 255, 127);  
    //imagecolortransparent($img, $img_magicpink);  

    // (Get its dimensions for copying)  
    list($w, $h) = getimagesize("./original.jpg");  

    // 2. Create the first copy  
    $copy = imagecreatefromjpeg("./original.jpg");  
    imagealphablending($copy, true);  

    $copy_magicpink = imagecolorallocate($copy, 255, 0, 255);  
    imagecolortransparent($copy, $copy_magicpink);  

    // 3. Create the mask  
    $mask = imagecreatetruecolor($w, $h);  
    imagealphablending($mask, true);  

    // 3-1. Set the masking colours  
    $mask_black = imagecolorallocate($mask, 0, 0, 0);  
    $mask_magicpink = imagecolorallocate($mask, 255, 0, 255);  
    imagecolortransparent($mask, $mask_black);  
    imagefill($mask, 0, 0, $mask_magicpink);  

    // 3-2. Draw the circle for the mask  
    $circle_x = $w/2;  
    $circle_y = $h/2;  
    $circle_w = 150;  
    $circle_h = 150;  
    imagefilledellipse($mask, $circle_x, $circle_y, $circle_w, $circle_h, $mask_black);  

    // 4. Copy the mask over the top of the copied image, and apply the mask as an alpha layer  
    imagecopymerge($copy, $mask, 0, 0, 0, 0, $w, $h, 100);  


    // 5. Do what you need to do to the image area  
    // My example is turning the original image gray and leaving the masked area as colour  
    $x = imagesx($img);  
    $y = imagesy($img);  
    $gray = imagecreatetruecolor($x, $y);  
    imagecolorallocate($gray, 0, 0, 0);  
    for ($i = 0; $i > 16) & 0xFF;  
        $g = ($rgb >> 8) & 0xFF;  
        $b = $rgb & 0xFF;  
         //for gray mode $r = $g = $b  
        $color = max(array($r, $g, $b));  
        $gray_color = imagecolorexact($img, $color, $color,   $color);  
        imagesetpixel($gray, $i, $j, $gray_color);  
      }  
    }  

    // 6. Merge the copy with the origianl - maintaining alpha  
    imagecopymergegray($gray, $copy, 0, 0, 0, 0, $w, $h, 100);  
    imagealphablending($gray, true);  
    imagecolortransparent($gray, $mask_magicpink);  

    header('Content-Type: image/png');  
    imagepng($gray);  
    imagedestroy($gray);  
like image 199
jsnfwlr Avatar answered Oct 21 '22 03:10

jsnfwlr