Why is the output to this 20, and not 22? Seeing as you're adding 10 + 0xA(which is 10 in HEX) + 2.
$a = 010;
$b = 0xA;
$c = 2;
print $a + $b + $c;
Output: 20.
It's correct!
(Because the first number is octal
so if you want it to be interpreted as a decimal you have to remove the first 0)
Se:
$a = 010; //Octal -> 8
$b = 0xA; //Hex -> 10
$c = 2; //Dec -> 2
print $a + $b + $c; //20
Output:
20
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