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Quite simply in PHP I have a date of 8th January 2011, in the format 08-01-11 - when I run this into strtotime and convert it back into a different date format, it reverts back to 1st August 2011 - not ideal!
Is there any easy way around this, rather than having to place everything into different arrays/variables and back again?
Thank you!
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In the below example, we have date 2019-09-15 in YYYY-MM-DD format, and we will convert this to 15-09-2019 in DD-MM-YYYY format. $orgDate = "2019-09-15"; $newDate = date("d-m-Y", strtotime($orgDate));
The strtotime() function parses an English textual datetime into a Unix timestamp (the number of seconds since January 1 1970 00:00:00 GMT). Note: If the year is specified in a two-digit format, values between 0-69 are mapped to 2000-2069 and values between 70-100 are mapped to 1970-2000.
Code for converting a string to dateTime$date = strtotime ( $input ); echo date ( 'd/M/Y h:i:s' , $date );
strtotime expects a "English textual datetime" (according to the manual), which Y-D-M is not. Any time strtotime returns false, it simply doesn't understand your string, which in this application is expected.
The perfect solution would be for the US to use the correct date format in the first place... ;0)
I do this to get around it:
$date = "31/12/2012";
$bits = explode('/',$date);
$date = $bits[1].'/'.$bits[0].'/'.$bits[2];
$date is now strtotimeable
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