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I have 3 files 1) show_createtable.html 2) do_showfielddef.php 3) do_showtble.php
1) First file is for creating a new table for a data base, it is a fom with 2 inputs, Table Name and Number of Fields. THIS WORKS FINE!
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
</head>
<body>
<h1>Step 1: Name and Number</h1>
<form method="post" action="do_showfielddef.php" />
<p><strong>Table Name:</strong><br />
<input type="text" name="table_name" size="30" /></p>
<p><strong>Number of fields:</strong><br />
<input type="text" name="num_fields" size="30" /></p>
<p><input type="submit" name="submit" value="go to step2" /></p>
</form>
</body>
</html>
2) this script validates fields and createa another form to enter all the table rows. This for also WORKS FINE!
<?php
//validate important input
if ((!$_POST[table_name]) || (!$_POST[num_fields])) {
header( "location: show_createtable.html");
exit;
}
//begin creating form for display
$form_block = "
<form action=\"do_createtable.php\" method=\"post\">
<input name=\"table_name\" type=\"hidden\" value=\"$_POST[table_name]\">
<table cellspacing=\"5\" cellpadding=\"5\">
<tr>
<th>Field Name</th><th>Field Type</th><th>Table Length</th>
</tr>";
//count from 0 until you reach the number fo fields
for ($i = 0; $i <$_POST[num_fields]; $i++) {
$form_block .="
<tr>
<td align=center><input type=\"texr\" name=\"field name[]\"
size=\"30\"></td>
<td align=center>
<select name=\"field_type[]\">
<option value=\"char\">char</option>
<option value=\"date\">date</option>
<option value=\"float\">float</option>
<option value=\"int\">int</option>
<option value=\"text\">text</option>
<option value=\"varchar\">varchar</option>
</select>
</td>
<td align=center><input type=\"text\" name=\"field_length[]\" size=\"5\">
</td>
</tr>";
}
//finish up the form
$form_block .= "
<tr>
<td align=center colspan=3><input type =\"submit\" value=\"create table\">
</td>
</tr>
</table>
</form>";
?>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Create a database table: Step 2</title>
</head>
<body>
<h1>defnie fields for <? echo "$_POST[table_name]"; ?>
</h1>
<? echo "$form_block"; ?>
</body>
</html>
Problem is here 3) this form creates the tables and enteres them into the database. I am getting an error on line 37 "Parse error: syntax error, unexpected $end in /home/admin/domains/domaina.com.au/public_html/do_createtable.php on line 37"
<?
$db_name = "testDB";
$connection = @mysql_connect("localhost", "admin_user", "pass")
or die(mysql_error());
$db = @mysql_select_db($db_name, $connection)
or die(mysql_error());
$sql = "CREATE TABLE $_POST[table_name](";
for ($i = 0; $i < count($_POST[field_name]); $i++) {
$sql .= $_POST[field_name][$i]." ".$_POST[field_type][$i];
if ($_POST[field_length][$i] !="") {
$sql .=" (".$_POST[field_length][$i]."),";
} else {
$sql .=",";
}
$sql = substr($sql, 0, -1);
$sql .= ")";
$result = mysql_query($sql, $connection) or die(mysql_error());
if ($result) {
$msg = "<p>" .$_POST[table_name]." has been created!</p>";
?>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Create A Database Table: Step 3</title>
</head>
<body>
<h1>Adding table to <? echo "$db_name"; ?>...</h1>
<? echo "$msg"; ?>
</body>
</html>
493
An Unexpected end of file error in a Bash script usually occurs when you there is a mismatched structure somewhere in the script. If you forget to close your quotes, or you forget to terminate an if statement, while loop, etc, then you will run into the error when you try to execute your Bash script.
That error means that PHP has finished analyzing your code, but you forgot to close a symbol somewhere in your page. Its either you forgot to close a quote, bracket, parenthesis or comma.
$result = mysql_query($sql, $connection) or die(mysql_error());
if ($result) {
$msg = "<p>" .$_POST[table_name]." has been created!</p>";
}
you missing a } in your last if statement, and your for loop is missing a } too
for ($i = 0; $i < count($_POST[field_name]); $i++) {
$sql .= $_POST[field_name][$i]." ".$_POST[field_type][$i];
if ($_POST[field_length][$i] !="") {
$sql .=" (".$_POST[field_length][$i]."),";
} else {
$sql .=",";
}
}
This error message means that a control structure block isn’t closed properly. In your case the closing } of some of your control structures like the for loop or the last if are missing.
You should use proper indentation and an editor that highlights bracket pairs to have a visual aid to avoid such errors.
43
You must close the for expression block:
for ($i = 0; $i < count($_POST[field_name]); $i++) {
$sql .= $_POST[field_name][$i]." ".$_POST[field_type][$i];
// ...
}
Your for loop is not terminated. You are missing a }
for ($i = 0; $i < count($_POST[field_name]); $i++) {
$sql .= $_POST[field_name][$i]." ".$_POST[field_type][$i];
}
And as pointed by others there is also a missing } for the last if statement:
if ($result) {
$msg = "< p>" .$_POST[table_name]." has been created!< /p>";
}
37
in your php.ini (php configuration) change :
short_open_tag = Off
you opened php tag shortly at line 1
just find and replace all <? with <?php
44
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