PHP switch statement inside for loop

Question

a have very simple problem here is my code:

$imax = 3;
$licenses = array('pub1','pub2','pub3');

for ($i=0; $i<=$imax; $i++) {

$pub = $licenses[$i];

switch ($pub){
case 'pub1': $pubtitle = "Pub title 1";
case 'pub2': $pubtitle = "Pub title 2";
case 'pub3': $pubtitle = "Pub title 3";
}

echo $pubtitle;

}

output is:

Pub title 3
Pub title 3
Pub title 3

I trying to put $pubtitle to an array, but its not working too :(

Answer 1

You're missing your break statement which stops execution of your switch statement. Without it everything "falls through" to the last statement which sets $pubtitle to "Pub Title 3";

switch ($pub){
   case 'pub1': $pubtitle = "Pub title 1"; break;
   case 'pub2': $pubtitle = "Pub title 2"; break;
   case 'pub3': $pubtitle = "Pub title 3"; break;
}

Answer 2

You need to add break; at the end of each case.

switch ($pub){
case 'pub1': $pubtitle = "Pub title 1"; break;
case 'pub2': $pubtitle = "Pub title 2"; break;
case 'pub3': $pubtitle = "Pub title 3"; break;
}