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php simple html dom parse img html5 attributes?

How to use simple html dom parse img html5 attribute: data-original

$htmls = '<img class="lazy" alt="Nubifragio a Verbania , ferite 2 turiste  Gravi danni, chiesto stato di calamità    foto" title="Nubifragio a Verbania , ferite 2 turiste  Gravi danni, chiesto stato di calamità    foto" data-original="http://www.repubblica.it/images/2012/08/26/130634575-506cc9ae-11b8-4a53-920c-539a3811e46b.jpg" src="http://www.repubblica.it/static/images/homepage/2012/lazy.png" width="130" height="98" style="display: inline; ">';
$html = str_get_html($htmls);
$fata = $html->find('img'); 
foreach($fata as $newimage){
    echo $newimage->data-original; //0
    echo $newimage->src; //http://www.repubblica.it/static/images/homepage/2012/lazy.png
}

I could get the attribute src, but data-original return 0

like image 560
Giberno Avatar asked Aug 26 '12 15:08

Giberno


2 Answers

$newimage->data-original;

means

$newimage->data - original;

A way round this is to try:

$property = 'data-original';
$newimage->$property;

or, to use the alternative syntax:

$newimage['data-original'];
like image 137
Rich Bradshaw Avatar answered Sep 19 '22 12:09

Rich Bradshaw


Just an FYI:

I tried:

$newimage['data-original'];

but this is what worked for me:

$property = 'data-original';
$newimage->$property;
like image 45
Chad Avatar answered Sep 23 '22 12:09

Chad