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I need help. I'm doing this:
round($myvar,2);
And this is the number I'm getting: 9.779999999999999€
With the other variables it works just fine, any idea how to fix this?
659
Example #1 round() examples php echo round(3.4); // 3 echo round(3.5); // 4 echo round(3.6); // 4 echo round(3.6, 0); // 4 echo round(1.95583, 2); // 1.96 echo round(1241757, -3); // 1242000 echo round(5.045, 2); // 5.05 echo round(5.055, 2); // 5.06 ?>
The ceil() function rounds a number UP to the nearest integer, if necessary. Tip: To round a number DOWN to the nearest integer, look at the floor() function. Tip: To round a floating-point number, look at the round() function.
Description. The ROUND function rounds a number to a specified number of digits. For example, if cell A1 contains 23.7825, and you want to round that value to two decimal places, you can use the following formula: =ROUND(A1, 2) The result of this function is 23.78.
The floor() function rounds a number DOWN to the nearest integer, if necessary, and returns the result. Tip: To round a number UP to the nearest integer, look at the ceil() function. Tip: To round a floating-point number, look at the round() function.
I did this:
<?php echo round(9.7752,2);?>
And I got: 9.779999999999999
I believe it's something in php.ini as @MarkBaker said.. But, I fixed it by doing:
<?php echo number_format($myvar,2);
And I got exactly what I wanted. Thanks guys for the help!
125
what problem I encounter is that round(18.203,2) = 18.2 ,then json_encode(...) = 18.199999999 . so I find the solution is json_encode(strval(round(18.203,2))) = 18.2 it works
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