PHP regular expression to match lines starting with a special character

Question

I have a text file with some configuration value. There a comment starts with a # I am trying to find a regular expression pattern that will find out all the lines that start with a #

So, sample file:

1st line
#test line this 
line #new line
aaaa #aaaa
bbbbbbbbbbb#
cccccccccccc
#ddddddddd

I want to find

#test line this 
#ddddddddd

because only these two lines start with # I tried the following code:

preg_match_all("/^#(.*)$/siU",$text,$m);
var_dump($m);

But it always outputs empty array. Anyone can help?

Answer 1

You forgot the multiline modifier (and you should not use the singleline modifier; also the case-insensitive modifier is unnecessary as well as the ungreedy modifier):

preg_match_all("/^#(.*)$/m",$text,$m);

Explanation:

• /m allows the ^ and $ to match at the start/end of lines, not just the entire string (which you need here)
• /s allows the dot to match newlines (which you don't want here)
• /i turns on case-insensitive matching (which you don't need here)
• /U turns on ungreedy matching (which doesn't make a difference here because of the anchors)

A PHP code demo:

$text = "1st line\n#test line this \nline #new line\naaaa #aaaa\nbbbbbbbbbbb#\ncccccccccccc\n#ddddddddd"; 
preg_match_all("/^#(.*)$/m",$text,$m);
print_r($m[0]);

Results:

[0] => #test line this 
[1] => #ddddddddd