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I want user only input 0-9 and only once "."
patt = /[^0-9(.{1})]/ 1.2222 -> true 1.2.2 -> false (only once '.') help me , thank !
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[0-9]+|[0-9]+). This regular expression matches an optional sign, that is either followed by zero or more digits followed by a dot and one or more digits (a floating point number with optional integer part), or that is followed by one or more digits (an integer).
In PHP, the Float data type is used to set fractional values. A float is a number with a decimal point and can be extended to exponential form. Float is also called a floating-point number. Various ways to represent float values are 3.14, 4.75, 5.88E+20, etc.
PHP Integers An integer data type is a non-decimal number between -2147483648 and 2147483647 in 32 bit systems, and between -9223372036854775808 and 9223372036854775807 in 64 bit systems. A value greater (or lower) than this, will be stored as float, because it exceeds the limit of an integer.
The is_float() function checks whether a variable is of type float or not. This function returns true (1) if the variable is of type float, otherwise it returns false.
this is what you're looking for
$re = "~ #delimiter ^ # start of input -? # minus, optional [0-9]+ # at least one digit ( # begin group \. # a dot [0-9]+ # at least one digit ) # end of group ? # group is optional $ # end of input ~xD"; this only accepts "123" or "123.456", not ".123" or "14e+15". If you need these forms as well, try is_numeric
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/^-?(?:\d+|\d*\.\d+)$/ This matches normal floats e.g. 3.14, shorthands for decimal part only e.g. .5 and integers e.g. 9 as well as negative numbers.
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