php preg_match to match chars at end of the string

Question

I have the below if statement, and it never returns True. What is wrong?

I am new to PHP and regular expressions.

$String = '123456';
$Pattern = "/\d{2}$/";

// I intend to match '56', which are the last two digits of the string.

if(preg_match($Pattern $String, $matches))
{
    echo 'Matched';
}

If the $Pattern is "/^\d{2}/", true is returned and matched the number '12';

---

My mistake. The above code works well.

In the actual code, the $String is assigned from a variable and it always end up with a dot which I was unaware of.

The requirement to match the last two digits above is just for issue explanation. The expression is required in actual code.

Answer 1

You are correct.

$String = '123456';
$Pattern = "/\d{2}$/";
$Pattern2 = "/^\d{2}/";

if(preg_match($Pattern, $String, $matches))
{
    print_r($matches); // 56
}

if(preg_match($Pattern2, $String, $matches))
{
    print_r($matches); // 12
}