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I need to pass a function as a parameter to another function and then call the passed function from within the function...This is probably easier for me to explain in code..I basically want to do something like this:
function ($functionToBeCalled) { call($functionToBeCalled,additional_params); } Is there a way to do that.. I am using PHP 4.3.9
Thanks!
274
There is another type of function known as PHP Parameterized functions, these are the functions with pre defined parameters. You'll pass any number of parameters inside a function. These passed parameters act as variables in your function. They are declared inside the brackets, after the function name.
Just to add to the others, you can pass a function name: function someFunc($a) { echo $a; } function callFunc($name) { $name('funky! '); } callFunc('someFunc');
Definition and Usage. The is_callable() function checks whether the contents of a variable can be called as a function or not. This function returns true (1) if the variable is callable, otherwise it returns false/nothing.
I think you are looking for call_user_func.
An example from the PHP Manual:
<?php function barber($type) { echo "You wanted a $type haircut, no problem"; } call_user_func('barber', "mushroom"); call_user_func('barber', "shave"); ?> If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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