I am a newbie of PHP. I study it from php.net
, but I found a problem today.
class foo {
var $bar = 'I am bar.';
}
$foo = new foo();
$bar = 'bar';
$baz = array('foo', 'bar', 'baz', 'quux');
echo "{$foo->$bar}\n";
echo "{$foo->$baz[1]}\n";
The documentation(http://php.net/manual/en/language.types.string.php) say that the above example will output:
I am bar.
I am bar.
But I get the different output run on my PC(PHP 7):
I am bar.
<b>Notice</b>: Array to string conversion in ... on line <b>9</b><br />
<b>Notice</b>: Undefined property: foo::$Array in ... on line <b>9</b><br />
Why?
This should work with PHP 7:
class foo {
var $bar = 'I am bar.';
}
$foo = new foo();
$bar = 'bar';
$baz = array('foo', 'bar', 'baz', 'quux');
echo "{$foo->$bar}\n";
echo "{$foo->{$baz[1]}}\n";
This is caused because in PHP 5 the following line:
echo "{$foo->$baz[1]}\n";
is interpreted as:
echo "{$foo->{$baz[1]}}\n";
While in PHP 7 it's interpreted as:
echo "{{$foo->$baz}[1]}\n";
And so in PHP 7 it's passing the entire array to $foo
instead of just that element.
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