I am using PHP 5.3 stable release and sometimes I encounter very inconsistent behaviours. As far as I know in inheritance all attributes and methods(private, public and protected) in super class are passed child class.
class Foo
{
private $_name = "foo";
}
class Bar extends Foo
{
public function getName()
{
return $this->_name;
}
}
$o = new Bar();
echo $o->getName();
//Notice: Undefined property: Bar::$_name in ...\test.php on line 11
But when Foo::$_name attribute is defined "public" it doesn't give error. PHP has own OO rules???
Thanks
Edit: Now all things are clear. Actually I was thinking in "inheritance" a new class is created and inherits all members independent from its ancestor. I didn't know "accessing" rules and inheritance rules are the same.
Edit According to your comments this snippet should give an error. But it is working.
class Foo
{
private $bar = "baz";
public function getBar()
{
return $this->bar;
}
}
class Bar extends Foo
{}
$o = new Bar;
echo $o->getBar(); //baz
From PHP Manual:
The visibility of a property or method can be defined by prefixing the declaration with the keywords
public
,protected
orprivate
. Class members declaredpublic
can be accessed everywhere. Members declaredprotected
can be accessed only within the class itself and by inherited and parent classes. Members declared asprivate
may only be accessed by the class that defines the member.
class A
{
public $prop1; // accessible from everywhere
protected $prop2; // accessible in this and child class
private $prop3; // accessible only in this class
}
And No, this is not different from other languages implementing the same keywords.
Regarding your second edit and code snippet:
No, this should not give an error because getBar()
is inherited from Foo
and Foo
has visibility to $bar
. If getBar()
was defined or overloaded in Bar
it would not work. See http://codepad.org/rlSWx7SQ
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