Menu
I am using a simple php script to look for an element in an array like
$restricted = array('root/base', 'root2' );
print_r($restricted);
if( array_search('root/base', $restricted) ){
echo "1";
} else {
echo "0";
}
But I am always getting the following output
Array ( [0] => root/base [1] => root2 ) 0
This means that the array_search is failing to find the element in the given array. Can anybody show some light on whats happening?
I tried to replace array_search() with in_array() also. But that too returned the same error.
588
The main difference between both the functions is that array_search() usually returns either key or index whereas in_array() returns TRUE or FALSE according to match found in search. Value: It specifies the value that needs to be searched in an array.
The in_array() function is an inbuilt function in PHP that is used to check whether a given value exists in an array or not. It returns TRUE if the given value is found in the given array, and FALSE otherwise.
PHP's in_array() function is really slow.
in_array() function is utilized to determine if specific value exists in an array. It works fine for one dimensional numeric and associative arrays.
From PHP DOC
array_search — Searches the array for a given value and returns the corresponding key if successful
The index is 0 that is why you think its fails
Use
array_search('root/base', $restricted) !== false
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With
