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Given the command:
/usr/bin/php -c /path/to/custom/php.ini /path/to/script.php
I'd like to get the internal options:
-c /path/to/custom/php.ini
Things I've tried that do not work:
$argv contains ['/path/to/script.php']
getopt('c') contains []
$_ENV does not contain it$_SERVER does not contain itI've also looked for a PHP_* constant (such as PHP_BINARY) but cannot find one for these arguments.
Is there any way to get these arguments? Note that I am not trying to obtain the loaded ini file but any arguments that might be present here.
586
To get the number of arguments that were passed into your function, call func_num_args() and read its return value. To get the value of an individual parameter, use func_get_arg() and pass in the parameter number you want to retrieve to have its value returned back to you.
PHP $_GET is a PHP super global variable which is used to collect form data after submitting an HTML form with method="get". $_GET can also collect data sent in the URL. Assume we have an HTML page that contains a hyperlink with parameters: <html>
The func_num_args() function can return the number of arguments passed into current user-defined function. This function can generate a warning if called from outside of a user-defined function.
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PHP has no internal way of doing this, so you are going to have to rely on certain system information and permissions.
$pid = getmypid();
$ps = `ps aux | grep $pid`;
$command = substr($ps, strpos($ps, '/usr/bin/php'));
$args = explode(' ', $command); //not pretty, should probably use preg
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