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My validate function looks like that
function validate($data, $data2 = 0, $type)
{
...
Function call example
if ($result = validate($lname, 'name') !== true)
response(0, $result, 'lname');
As you see, my validate function has 3 input vars. I'm not using second var - $data2 often, that's why set it to 0 by default. But when I'm calling this function as given example (as far as I know it means $data=$lname, $data2=0, $type='name') getting error message
Missing argument 3 ($type) for validate()
How can I fix that?
715
PHP Function Arguments Information can be passed to functions through arguments. An argument is just like a variable. Arguments are specified after the function name, inside the parentheses. You can add as many arguments as you want, just separate them with a comma.
The missing argument is an object that triggers an error if and only if it is the result of evaluating a symbol. No error is produced when a function call evaluates to the missing argument object.
The default value is used for any missing arguments in PHP 7. x versions. In PHP 8, we can pass the arguments to a function based on the parameter name, rather than passing the parameter position. Order doesn't matter in PHP 8, it is allowed to skip default values randomly and it is also self-documenting.
Setting Default Values for Function parameterPHP allows us to set default argument values for function parameters. If we do not pass any argument for a parameter with default value then PHP will use the default set value for this parameter in the function call. Example: PHP.
Missing argument 3 ($type) for validate()
Always list optional arguments as the last arguments. Since PHP doesn't have named parameters nor "overloading ala Java", that's the only way:
function validate($data, $type, $data2 = 0) {
}
You should at least set the $type in this line:
function validate($data, $data2 = 0, $type)
at NULL or '' as you can see here:
function validate($data, $data2 = 0, $type = null)
PHP let you to set a value for the parameters, but you can't define a parameter WITHOUT a preset value AFTER parameter(s) which HAVE a preset value. So if you need to always specify the third param, you have to switch the second and the third like this:
function validate($data, $type, $data2 = 0)
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