PHP Filtering an array for 1 url

Question

I made a script that creates an array of urls scraped from a page and I want to filter the array for just 1 certain url. The array currently looks like this:

Array
(
    [0] => index.jsp
    [1] => feedback.jsp
    [2] => faq.jsp
    [3] => donate.jsp
    [4] => contact.jsp
    [5] => widgetmaker.jsp
    [11] => http://www.example.com/myaccount/accountactivation?_mska_tok=tON-3yIN1n5TVrFAXT3Q&_tgt_url=http%3A%2F%2Fanothersite.com%2Fxml.php
    [12] => http://www.example.com/myaccount/accountactivation?_mska_tok=tON-3yIN1n5TVrFAXT3Q&_tgt_url=http%3A%2F%2Fanothersite.com%2Fxml.php
    [13] => http://www.example.com/myaccount/accountactivation?_mska_tok=tON-3yIN1n5TVrFAXT3Q&_tgt_url=http%3A%2F%2Fanothersite.com%2Fxml.php
    [14] => http://www.example.com/myaccount/accountactivation?_mska_tok=tON-3yIN1n5TVrFAXT3Q&_tgt_url=http%3A%2F%2Fanothersite.com%2Fxml.php
    [15] => http://www.example.com/myaccount/accountactivation?_mska_tok=tON-3yIN1n5TVrFAXT3Q&_tgt_url=http%3A%2F%2Fanothersite.com%2Fxml.php
)

And what I want it to do is grab one of the "http://www.example.com/myaccount/accountactivation?_mska_tok=tON-3yIN1n5TVrFAXT3Q&_tgt_url=http%3A%2F%2Fanothersite.com%2Fxml.php" links. How do I do this?

Answer 1

If I understand correctly, you want to get only fully-qualified (absolute) URLs:

$filtered = array_filter($urls, function($url) {
    if (strpos($url, 'http://') === 0) return true;
    return false;
});

If you want both http and https urls:

$filtered = array_filter($urls, function($url) {
    if (preg_match('#^https?://#', $url)) return true;
    return false;
});

If you only want exact matches:

$filtered = array_filter($urls, function($url) {
    if ($url == 'http://full/url/goes/here') return true;
    return false;
});

If you only want to get the first one then:

$url = $filtered[0];