this is a really basic question (I hope). Most of the exception handling I have done has been with c#. In c# any code that errors out in a try catch block is dealt with by the catch code. For example
try
{
int divByZero=45/0;
}
catch(Exception ex)
{
errorCode.text=ex.message();
}
The error would be displayed in errorCode.text. If I were to try and run the same code in php however:
try{
$divByZero=45/0;
}
catch(Exception ex)
{
echo ex->getMessage();
}
The catch code is not run. Based on my limeted understanding, php needs a throw. Doesn't that defeat the entire purpose of error checking? Doesn't this reduce a try catch to an if then statement? if(dividing by zero)throw error Please tell me that I don't have to anticipate every possible error in a try catch with a throw. If I do, is there anyway to make php's error handling behave more like c#?
You could also convert all your php errors with set_error_handler() and ErrorException into exceptions:
function exception_error_handler($errno, $errstr, $errfile, $errline )
{
throw new ErrorException($errstr, 0, $errno, $errfile, $errline);
}
set_error_handler("exception_error_handler");
try {
$a = 1 / 0;
} catch (ErrorException $e) {
echo $e->getMessage();
}
PHP's try-catch was implemented later in the language's life, and so it only applies to user-defined exceptions.
If you really want to handle actual errors, set your own error handler.
To define and catch exceptions:
function oops($a)
{
if (!$a) {
throw new Exception('empty variable');
}
return "oops, $a";
}
try {
print oops($b);
} catch (Exception $e) {
print "Error occurred: " . $e->getMessage();
}
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