I want to be able to figure out the month of the current date variable. I'm ex vb.net and the way to do it there is just date.Month
. How do I do this in PHP?
Thanks,
Jonesy
I used date_format($date, "m"); //01, 02..12
This is what I wanted, question now is how do I compare this to an int since $monthnumber = 01
just becomes 1
php $transdate = date('m-d-Y', time()); echo $transdate; $month = date('m', strtotime($transdate)); if ($month == "12") { echo "<br />December is the month :)"; } else { echo "<br /> The month is probably not December"; } ?>
The Excel MONTH function extracts the month from a given date as number between 1 to 12. You can use the MONTH function to extract a month number from a date into a cell, or to feed a month number into another function like the...
Use the new Date() constructor to get a date object. Call the getMonth() method on the object and add 1 to the result. The getMonth method returns a zero-based month index so adding 1 returns the current month.
See http://php.net/date
date('m')
or date('n')
or date('F')
...
Update
m Numeric representation of a month, with leading zeros 01 through 12
n Numeric representation of a month, without leading zeros 1 through 12
F Alphabetic representation of a month January through December
....see the docs link for even more options.
What does your "data variable" look like? If it's like this:
$mydate = "2010-05-12 13:57:01";
You can simply do:
$month = date("m",strtotime($mydate));
For more information, take a look at date and strtotime.
EDIT:
To compare with an int, just do a date_format($date,"n");
which will give you the month without leading zero.
Alternatively, try one of these:
if((int)$month == 1)...
if(abs($month) == 1)...
Or something weird using ltrim, round, floor... but date_format() with "n" would be the best.
$unixtime = strtotime($test);
echo date('m', $unixtime); //month
echo date('d', $unixtime);
echo date('y', $unixtime );
as date_format uses the same format as date ( http://www.php.net/manual/en/function.date.php ) the "Numeric representation of a month, without leading zeros" is a lowercase n .. so
echo date('n'); // "9"
As it's not specified if you mean the system's current date or the date held in a variable, I'll answer for latter with an example.
<?php
$dateAsString = "Wed, 11 Apr 2018 19:00:00 -0500";
// This converts it to a unix timestamp so that the date() function can work with it.
$dateAsUnixTimestamp = strtotime($dateAsString);
// Output it month is various formats according to http://php.net/date
echo date('M',$dateAsUnixTimestamp);
// Will output Apr
echo date('n',$dateAsUnixTimestamp);
// Will output 4
echo date('m',$dateAsUnixTimestamp);
// Will output 04
?>
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