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How can I convert spaces in string into %20?
Here is my attempt:
$str = "What happens here?";
echo urlencode($str);
The output is "What+happens+here%3F", so the spaces are not represented as %20.
What am I doing wrong?
756
The trim() function removes whitespace and other predefined characters from both sides of a string. Related functions: ltrim() - Removes whitespace or other predefined characters from the left side of a string. rtrim() - Removes whitespace or other predefined characters from the right side of a string.
Approach 1: Using the str_replace() and str_split() functions in PHP. The str_replace() function is used to replace multiple characters in a string and it takes in three parameters. The first parameter is the array of characters to replace.
Using str_replace() Method: The str_replace() method is used to remove all the special characters from the given string str by replacing these characters with the white space (” “).
if you have a parameter $string and want to replace it's apace to underscore(_). $string = "Hello All."; $newString = str_replace(' ', '_', $string);
Use the rawurlencode function instead.
113
The plus sign is the historic encoding for a space character in URL parameters, as documented in the help for the urlencode() function.
That same page contains the answer you need - use rawurlencode() instead to get RFC 3986 compatible encoding.
29
I believe that, if you need to use the %20 variant, you could perhaps use rawurlencode().
27
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