this is my class:
class toyota extends car {
function drive() {
}
function break() {
}
}
class car {
function pre() {
}
}
Is there any way I can do so that when I run $car->drive(), $car->break() (or any other function in toyota), it would call $car->pre() first before calling the functions in toyota?
Yep. You could use protected
and some __call
magic:
class toyota extends car {
protected function drive() {
echo "drive\n";
}
protected function dobreak() {
echo "break\n";
}
}
class car {
public function __call($name, $args)
{
if (method_exists($this, $name)) {
$this->pre();
return call_user_func_array(array($this, $name), $args);
}
}
function pre() {
echo "pre\n";
}
}
$car = new toyota();
$car->drive();
$car->dobreak();
http://ideone.com/SGi1g
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