PHP checkbox set to check based on database value

Question

I have a system where people fill in their information and later can go back and edit certain parts, basically the enter personal info and check whether they want to know extra info, these bits of extra infos are checkboxes, 4 of them. the user will select up to any of the 4 and the database has 4 fields set to no, if they select one it changes to yes. I want them to be able to go back and deselect or reselect any of these 4 checkboxes, so what i want s for the checkboxes to be selected if the values is yes and unselected if the value is not.

the fields are tag_1, tag_2, tag_3, tag_4

Anyhelp greatly appreciated

I gather some kind of if statement but not sure how to involve it in a checkbox.

<label for="tag_1">Tag 1</label>
<input type="checkbox" name="tag_1" id="tag_1" value="yes" />

Ian

Answer 1

Extract the information from the database for the checkbox fields. Next change the above example line to: (this code assumes that you've retrieved the information for the user into an associative array called dbvalue and the DB field names match those on the HTML form)

<input type="checkbox" name="tag_1" id="tag_1" value="yes" <?php echo ($dbvalue['tag_1']==1 ? 'checked' : '');?>>

If you're looking for the code to do everything for you, you've come to the wrong place.

Answer 2

Add this code inside your input tag

<?php if ($tag_1 == 'yes') echo "checked='checked'"; ?>