Php check if object with property exists in array

Question

Let's assume I have the following PHP code:

$a = new a();
$a->id = 1;

I then have an array $m of objects of type type a (but they really could be of any type). I want to check if any object in m has property id equal to 1. In Java, I'd do something like:

myList
.stream()
.filter(x <- x.id == a.id)
.count();

In PHP I tried

in_array($a, $m)

but that didn't seem to do work, because obviously even if another object had the same ID it would still be a different object.

I could obviously use a loop, but as really I'd want to check if any object in an array n had a corresponding object with the same ID in m I'd rather avoid a nested loop.

Answer 1

PHP also has an array filtering functioning, which (for obvious reasons) is called array_filter() and does what you want, with anonymous functions.

function findAllWithId($objects, $id) {
    return array_filter($objects, function($toCheck) use ($id) { 
        return $toCheck->id == $id; 
    });
}