PHP Check if array element exists in any part of the string

Question

I know how to find if your string equals an array value:

$colors = array("blue","red","white");

$string = "white";

if (!in_array($string, $colors)) {
    echo 'not found';
}

...but how do I find if the string CONTAINS any part of the array values?

$colors = array("blue","red","white");

$string = "whitewash"; // I want this to be found in the array

if (!in_array($string, $colors)) {
    echo 'not found';
}

Answer 1

Or in one shot:

if( preg_match("(".implode("|",array_map("preg_quote",$colors)).")",$string,$m)) {
    echo "Found ".$m[0]."!";
}

This can also be expanded to only allow words that start with an item from your array:

if( preg_match("(\b(?:".implode("|",array_map("preg_quote",$colors))."))",$string,$m)) {

Or case-insensitive:

if( preg_match("(".implode("|",array_map("preg_quote",$colors)).")i",$string,$m)) {

CI with starting only:

if( preg_match("(\b(?:".implode("|",array_map("preg_quote",$colors))."))i",$string,$m)) {

Or anything really ;)