I am having trouble using openpyxl scripts in Komodo edit 9 and python 3.4 on Windows 7. I copied some openpyxl code to learn, but it won't execute from Komodo. I receive a permission error 13. I checked my path and python34 is present. The same script will run when I use IDLE or Command Prompt. My Komodo command is currently: %(python3) -u %F Any ideas on what may be causing this issue? The code and error are included below
from openpyxl import Workbook
from openpyxl.compat import range
from openpyxl.cell import get_column_letter
wb = Workbook()
dest_filename = 'empty_book.xlsx'
ws1 = wb.active
ws1.title = "range names"
for row in range(1, 40):
ws1.append(range(600))
ws2 = wb.create_sheet(title="Pi")
ws2['F5'] = 3.14
ws3 = wb.create_sheet(title="Data")
for row in range(10, 20):
for col in range(27, 54):
_ = ws3.cell(column=col, row=row, value="%s" % get_column_letter(col))
print(ws3['AA10'].value)
wb.save(filename = dest_filename)
-------Begin Error-----------
AA
Traceback (most recent call last):
File "C:\Users\PF15043\Desktop\Scripts\Ggizmo\excelReader.py", line 26, in <module>
wb.save(filename = dest_filename)
File "C:\Python34\lib\site-packages\openpyxl-2.3.0b1-py3.4.egg\openpyxl\workbook\workbook.py", line 254, in save
save_workbook(self, filename)
File "C:\Python34\lib\site-packages\openpyxl-2.3.0b1-py3.4.egg\openpyxl\writer\excel.py", line 195, in save_workbook
writer.save(filename, as_template=as_template)
File "C:\Python34\lib\site-packages\openpyxl-2.3.0b1-py3.4.egg\openpyxl\writer\excel.py", line 177, in save
archive = ZipFile(filename, 'w', ZIP_DEFLATED, allowZip64=True)
File "C:\Python34\lib\zipfile.py", line 923, in __init__
self.fp = io.open(file, modeDict[mode])
PermissionError: [Errno 13] Permission denied: 'empty_book.xlsx'
I faced the same problem yesterday, but because I dumbly let the workbook open while trying to run the script. Closing it fixed the issue.
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